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Mathematics 24 Online
OpenStudy (anonymous):

Two cards are drawn from a standard deck of 52 cards without replacement. Find the probability of the following events. (Enter your probabilities as fractions.) (a) The first is a jack and the second a queen. (b) Both cards are jacks.

OpenStudy (anonymous):

There are 4 of each type of card in a standard deck, so the probability of pulling a jack on the first draw is 4/52. SInce there is no replacement the deck is now 51 cards, meaning the probability of drawing a queen is now 4/51. In the second part the probability of getting a jack on the first draw is still 4/52, but now there is one fewer jack to find, meaning the probability of the second is 3/51

OpenStudy (anonymous):

Is there a base equation for this ? @LastTrainHome22

OpenStudy (anonymous):

the probability of an event is the number of favorable outcomes over the number of possible outcomes. Less of an equation, more of a defintion

OpenStudy (anonymous):

My mistake I forgot to include the final step. For each part you need to multiply the two individual probabilities. The probability of two independent events happening is equal to the product of the two individual events

OpenStudy (anonymous):

so part a would be (4/52)*(4/51) @LastTrainHome22

OpenStudy (anonymous):

Correct.

OpenStudy (anonymous):

@LastTrainHome22 thank you! again!

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