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Biology 19 Online
OpenStudy (anonymous):

HELP

OpenStudy (anonymous):

The population of a local species of beetle can be found using an infinite geometric series where a1 = 880 and the common ratio is one fourth. Write the sum in sigma notation, and calculate the sum (if possible) that will be the upper limit of this population. the summation of 880 times one fourth to the i minus 1 power, from i equals 1 to infinity. ; the sum is divergent the summation of 880 times one fourth to the i minus 1 power, from i equals 1 to infinity. ; the sum is 1,173 the summation of 880 times one fourth to the i power, from i equals 1 to infinity. ; the series is divergent the summation of 880 times one fourth to the i power, from i equals 1 to infinity. ; the sum is 1,173 @Miss_Panda

OpenStudy (anonymous):

What do u think so far.. Ur educated guess?

OpenStudy (anonymous):

I put D so far

OpenStudy (anonymous):

Ok.

OpenStudy (anonymous):

Not the answer tho

OpenStudy (anonymous):

Oh okay

OpenStudy (anonymous):

My answer would be the summation of 880 times one fourth to the i minus 1 power, from i equals 1 to infinity. ; the sum is 1,173 But to make sure i'll ask @sleepyjess

OpenStudy (anonymous):

@chycora

OpenStudy (anonymous):

Where did this question come from?

OpenStudy (anonymous):

A worksheet for school

OpenStudy (anonymous):

Oh, ok

OpenStudy (chycora):

yes

OpenStudy (anonymous):

While we are waiting can you confirm if my answer is correct? Given the exponential equation 3x = 27, what is the logarithmic form of the equation in base 10? x = log base 10 of 3, all over log base 10 of 27 x = log base 10 of 27, all over log base 10 of 3 x = log base 2 of 3, all over log base 2 of 27 x = log base 2 of 10, all over log base 2 of 3 I picked B

OpenStudy (anonymous):

@chycora

OpenStudy (chycora):

srry guys i can't help right kn i gt a ton of hw myself so i am so srry but nt today

OpenStudy (anonymous):

Okay, thats ok, thank you

OpenStudy (chycora):

yw so srry tho

OpenStudy (anonymous):

ok thank you anyway @chycora

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