Solve the equation by graphing. x^2-10x+24 = 0 First, graph the associated parabola by plotting the vertex and four additional points, two on each side of the vertex. Then, use the graph to give the solution(s) to the equation. If there is more than one solution, separate them with commas.
\(\bf x^2-10x+24 = 0 \\ \quad \\ \textit{vertex of a parabola}\\ \quad \\ {\color{red}{ 1}}x^2{\color{blue}{ -10}}x{\color{green}{ +24}}=0\qquad \left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\) use the vertex you found, and pick four points, two on either side of the vertex graph away, find the solutions solution for a quadratic, or parabola, means, the x-intercepts or where the graph touches the x-axis
thank you! so after I plug in my equation into that point and plot it that's my vertex then I JUST PLOT WHAT EVER ELSE ON EITHER SIDE? ( sorry for caps =o)
oh I love that site it can really help with these problems? =D
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