Mathematics
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OpenStudy (anonymous):
1) WILL BE GIVING MEDAL AND FAN!!!
Use the quadratic formula to solve 2y2 – 10y + 8 = 0.
a. {–4, –1}
b. {4, –1}
c. {–4, 1}
d. {4, 1}
11 years ago
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OpenStudy (kidrah69):
First list out your
a
b
c values
11 years ago
OpenStudy (kidrah69):
what are they?
11 years ago
OpenStudy (anonymous):
ok..I know how but....?
11 years ago
OpenStudy (anonymous):
ill do them rn
11 years ago
OpenStudy (zale101):
Factor out the common factor first.
11 years ago
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OpenStudy (zale101):
Then work your way on factoring the rest
11 years ago
OpenStudy (anonymous):
a. 2
b. 10
c. 8
11 years ago
OpenStudy (kidrah69):
it says to use the quadratic formula...not factor
11 years ago
OpenStudy (anonymous):
right?
11 years ago
OpenStudy (anonymous):
ohhh then im not sure sat all
11 years ago
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OpenStudy (zale101):
Oh, i just noticed that xD
11 years ago
OpenStudy (kidrah69):
b is wrong
11 years ago
OpenStudy (anonymous):
would it be A?
11 years ago
OpenStudy (kidrah69):
No the value
11 years ago
OpenStudy (zale101):
@brae , do you know what the quadratic formula look like?
11 years ago
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OpenStudy (kidrah69):
\[\frac{ x = -b ± \sqrt(b^2 - 4ac) }{ 2a } \]
11 years ago
OpenStudy (anonymous):
ummm...wait one sec, I have it in my notes
11 years ago
OpenStudy (kidrah69):
lol i posted it XD
11 years ago
OpenStudy (anonymous):
ohh thats right!!
11 years ago
OpenStudy (zale101):
kidrah, the x shouldn't be in the numerator :X
11 years ago
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OpenStudy (kidrah69):
my bad :P doesnt make a diffrence >_<
11 years ago
OpenStudy (zale101):
So @brae , what does the a, b, and c indicate in the quadratic formula, kidrah listed ?
11 years ago
OpenStudy (anonymous):
isnt it this?
a. 2
b. 10
c. 8
11 years ago
OpenStudy (zale101):
Do you have any idea for where constants came from?
11 years ago
OpenStudy (kidrah69):
B is still wrong
11 years ago
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OpenStudy (anonymous):
yes I learned it today
11 years ago
OpenStudy (kidrah69):
(2y^3) (-10y) (+8)
11 years ago
OpenStudy (kidrah69):
its not 10
11 years ago
OpenStudy (anonymous):
ohh is B -10
11 years ago
OpenStudy (kidrah69):
mhm
11 years ago
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OpenStudy (anonymous):
yay!
11 years ago
OpenStudy (kidrah69):
\[\frac{ x = -(-10) ± \sqrt((-10)^2 - 4(2)(8) }{ 2(2) } \]
11 years ago
OpenStudy (kidrah69):
now you just have to solve
11 years ago
OpenStudy (zale101):
The standard quadratic equation is ually written like this
\(\Large ax^2+bc+c=0\)
and there's a proof for this standard equation that converts to the qudratic formula where you solve x, only.
11 years ago
OpenStudy (anonymous):
Is the answer A??
11 years ago
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OpenStudy (anonymous):
i think lol
11 years ago
OpenStudy (anonymous):
maybe not ha
11 years ago
OpenStudy (zale101):
But since your variable is y
\(ay^2+by+c=0\)
\(2y^2 – 10y + 8 = 0\)
a=?
b-?
c=?
\(y=\LARGE \frac{-b\pm \sqrt{b^2-4ac}}{2a}\)
11 years ago
OpenStudy (zale101):
Plug and chug
11 years ago
OpenStudy (anonymous):
ok...
11 years ago
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OpenStudy (zale101):
and show your work :)
11 years ago
OpenStudy (anonymous):
ummm ok i messed up and is really confused lol
11 years ago
OpenStudy (anonymous):
@Zale101
11 years ago
OpenStudy (zale101):
Show me what you had.
11 years ago
OpenStudy (anonymous):
im confused
11 years ago
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OpenStudy (anonymous):
but its weird because i learned it today in class
11 years ago
OpenStudy (anonymous):
ohh ok so the answers there was 5 and -2
11 years ago
OpenStudy (zale101):
This is just an example i pulled off of google, but try to see how they got those two answers.
11 years ago
OpenStudy (anonymous):
ok
11 years ago
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OpenStudy (anonymous):
does anyone know the answer?
11 years ago
OpenStudy (anonymous):
@Zale101 @kidrah69
11 years ago
OpenStudy (wolf1728):
2y2 – 10y + 8 = 0
a=2
b=-10
c=8
x= [--10 +- sqroot (100 - 4*2*8)]/2*2
x = [10 +- sqroot(36)] /4
x = [10 + 6] / 4
x1= 4
x2 = [10 - 6] / 4
x2 = 4 / 4
x2=1
Answer is d
11 years ago
OpenStudy (anonymous):
can i tag u in other problems that i have to do?
11 years ago
OpenStudy (wolf1728):
okay - as long as it's not too many others
How about just one more problem?
11 years ago
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OpenStudy (anonymous):
ya thanks!
11 years ago