Find the radius of the circle whose equation is x² + y² = 4. 2 4 16
\(\LARGE x^2+y^2=r^2\) Now, what is the radius of x² + y² = 4 ?
That is the standard equation of circle now compare it :)
if \(r^2= Number\), then to figure out the radius alone, we take the square root of both sides if \(\Large \sqrt{r^2}= \sqrt{Number}\) if \(\Large r= \sqrt{Number}\)
16
No.
4 squared is 16.
it would be 16 if your equation was: x² + y² = 256 then the radius would be: \(\Large r=\sqrt{256}=16\)
bring the equation in a form where all the variables and constants are in the square form
I don't understand.
Is it 4 then?
\[x^2+y^2=(16)^2\] considering @Zale101 example
when we compare the equation with \[\x^2+y^2=r^2\] r=16
Here are some other example: x² + y² = 256 radius is 16; because x² + y² = (16)^2 x² + y² = 81, radius is 9; becausex² + y² = 9^2 x² + y² = 64, radius is 8, because x² + y² = 8^2
ur equation : \[x^2+y^2=(?)^2\]
x² + y² = 4, the radius for this is..?
2
Bingo!
All the best!!! :)
Thanks!
x² + y² = 4, the radius is 2 because x² + y² = 2^2
Anytime
wow too long :)
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