Mathematics
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OpenStudy (anonymous):
PLEASE HELP
Find an explicit rule for the nth term of the sequence.
-5, -25, -125, -625, ...
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OpenStudy (anonymous):
an = 5 -5n
an = 5 -5n + 1
an = -5 5n
an = -5 5n - 1
OpenStudy (welshfella):
first term = -5
second term = -5 * 5
third term = -5 * 5^2
4th term = -5 * 5^3
can you see the pattern?
OpenStudy (anonymous):
Yes as the terms increase so does the exponent
OpenStudy (welshfella):
yes and if the term is 2 the exponent is 1
and if term is 3 the exponent is 2
for the first term the exponent is 0
OpenStudy (anonymous):
Would it be C??
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OpenStudy (anonymous):
@welshfella
OpenStudy (welshfella):
no because the n = exponent
OpenStudy (anonymous):
That's the consistent pattern that's occurring, right
OpenStudy (anonymous):
Oh
OpenStudy (anonymous):
Ohhhh wait
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OpenStudy (welshfella):
its has to be c or d because of the -5
OpenStudy (anonymous):
Can't it be B because of the continuous addition to the exponent as the terms increase?
OpenStudy (welshfella):
no because the first term is -5 not 5
OpenStudy (anonymous):
Then it must be C because the exponent is being subtracted from, correct?
OpenStudy (anonymous):
*isn't
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OpenStudy (welshfella):
the way you have written the options is confusing
they should be
5 * (-5)^n
5 * (-5)^(n+1)
-5 * (5)^n
-5 * (5)^(n-1)
OpenStudy (welshfella):
check out a
n = 1:- a 1 = first term = 5*(-5)^1 = -25
OpenStudy (welshfella):
try d when n = 1
OpenStudy (welshfella):
a1 = -5 * (5)^(1-1) = -5 ^ 5^0 = -5 * 1 = -5
OpenStudy (welshfella):
* that should be -5 * 5^0
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OpenStudy (welshfella):
do you follow that ok?
OpenStudy (anonymous):
Did you use D in your last problem?
OpenStudy (welshfella):
a2 = -5*(5)^(2-1) = -5 * 5^1 = -5 * 5 = -25
OpenStudy (welshfella):
yes
OpenStudy (anonymous):
Would it be D then since the answer is -5?????
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OpenStudy (welshfella):
i used d for both calculations
OpenStudy (anonymous):
*?
OpenStudy (anonymous):
Oh I just saw it
OpenStudy (anonymous):
Thank you so much
OpenStudy (welshfella):
well you have to check a few not just the first
as you see it works for n = 1 and n = 2
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OpenStudy (anonymous):
Would you mind helping me with 2 more
OpenStudy (welshfella):
normally i would but i gotta go right now
OpenStudy (anonymous):
Oh alright. Thanks again!