The center of the ellipse is at: (-3, -6) (3, 6) (3, 4)
\[\frac{ (x-3)^2 }{ 9 }+\frac{ (y-6)^2 }{ 16 }=1\]
WHAT DO YOU THINK IT IS? >:}
I have absolutely NO idea. I don't understand ellipses..lol
Maybe it's A? Idk
I THINK YOUR RIGHT >:}}}
Anybody else have opinions? Lol
ACTUALITY ID GO WITH B!
do u have a picture of this that can help https://www.bing.com/images/search?q=+ellipse&view=detailv2&&&id=1EE7BD0397501CDC6A1D93351651386AEC64F554&selectedIndex=12&ccid=6kBUM5M7&simid=607988364026185536&thid=JN.LyPkI76jiIgfsYuSFO0VKw
(h,k) is the center of the equation
Idk what (h,k) is.
\[\huge\rm \frac{ (x-h)^2 }{ a^2}+\frac{ (y-k)^2 }{ b^2 }=1\] standard form of ellipse where (h,k) is the center
so what is h and k in the equation ?
Still don't know.
the answer will be B
the number with x in the parentheses is suppose to be h and number with y in the parentheses is k
sigh.
What?
THE ANSWER IS B THATS WHAT I SAID
.
What's that supposed to mean? @Nnesha
COULD I GET A MEDAL ? PLEAS
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