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Mathematics 21 Online
OpenStudy (anonymous):

can someone help me solve this problem?-- In order to make it easier to find the nth term of an geometric sequence given two terms of the sequence, several students decide to solve the formula for a geometric sequence for r. Which student has correctly done so? images attached

OpenStudy (anonymous):

OpenStudy (amistre64):

well its just arithmetic, how would you approach it?

OpenStudy (anonymous):

I am not really sure I have gone through notes and my teachers videos explaining it and I cant follow

OpenStudy (amistre64):

does subtraction undo multiplicaton? given: y = ab, does y-a = ab - a ?

OpenStudy (amistre64):

or rather, does ab-a = b?

OpenStudy (amistre64):

does 2(4) - 2 = 4?

OpenStudy (anonymous):

yeah

OpenStudy (amistre64):

y-a = ab - a yes, but thats not really what i was going for lol does: ab - a = b? and for an example: does 2(4) - 2 = 4?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

prove it ..

OpenStudy (anonymous):

how? 2+2=4 and 2x2=4

OpenStudy (amistre64):

2(4) - 2 = 4 what is 2(4) - 2 ?

OpenStudy (anonymous):

oh 8 lol sorry it late and im kinda tired

OpenStudy (amistre64):

then in general: ab - a is not b subtracing a1 from both sides is pointless.

OpenStudy (amistre64):

2(4) - 2 = 8-2 = 6 and 6 is not 4

OpenStudy (amistre64):

now, how do we undo a power?

OpenStudy (anonymous):

umm divide?

OpenStudy (amistre64):

no .. r^2, to undo it we root it sqrt(r^2) = r^(2/2) = r nrt(r^n) = r^(n/n) = r

OpenStudy (anonymous):

ahh got it

OpenStudy (amistre64):

good :)

OpenStudy (anonymous):

hmm would it be the second one?

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@Tommynaut

OpenStudy (amistre64):

does the second one root it properly? is r^[(n-1)/2] = r for all n?

OpenStudy (anonymous):

no?

OpenStudy (amistre64):

why is that a question? is (n-1)/2 = 1 for all n, or can you find a value of n that makes it false?

OpenStudy (anonymous):

ohh I that makes sense its hard for me to see it without the numbers

OpenStudy (amistre64):

let n=11 .... is (11-1)/2 = 1 ?

OpenStudy (amistre64):

if not, then talking a sqrt is not an appropriate root

OpenStudy (amistre64):

if numbers make it easier, then use numbers .. 10 = 5 r^(3) what is r?

OpenStudy (amistre64):

21 = 7 r^12 make life simpler for yourself ...

OpenStudy (tommynaut):

As @amistre64 has implied, we can rule out Nelly and Alison because their methods don't work at all - they try and subtract a1 from both sides but don't actually end up doing it. If we look at the first two people's solutions, they both start with correctly dividing through both sides by a1. However, the next step is to cancel the n-1 which is the power of r. To do that, we have to take the (n-1) root of both sides. Cinthia just takes the square root of both sides (when there's no number on the root, it means it's the 2nd root, or the square root). Antoinette DOES take the (n-1) root of both sides. So who ends up with the right answer?

OpenStudy (anonymous):

wouldn't r be the sequence? or the first number in the sequence

OpenStudy (amistre64):

r is used since it is the first letter in the word "ratio" r is a common ratio among the terms .... its not any term perse, its how we build the sequence.

OpenStudy (anonymous):

it would be the first person. I didn't notice Cynthia only used one

OpenStudy (amistre64):

a1 is the 1th term, the first term, the term of A that is at the start, first place.

OpenStudy (anonymous):

That makes so much more sense. my teacher only explained it very briefly and didn't even mention that

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