Question

Ok, I got this : 4.0460502 but am I correct?

Answer 1

The answer I got is D!

Answer 2

and your work ??
i'm sorry but tht's important

Answer 3

yeah good.
4.04 something..

Answer 4

dont need my work because I"m correct :)

Answer 5

but still i would like to see it

Answer 6

unless you just wana see it

Answer 7

yes i want to see it

Answer 8

You need to show work if you are wrong, as to figure out where you have done wrong, but if you are correct, then you are correct, no need to show your work..

Answer 9

Excatly, and I"m right BIG GURL

Answer 10

nope still work is important

Answer 11

*exactly

Answer 12

And when @Nnesha wants to see your work, then show her, may be finally you come out to be wrong.. :P

Answer 13

ok fine here:

Answer 14

ok fine here: Remove parentheses around 0.65.
4000⋅0.65z=700
Divide each term in the equation by 4000.

Answer 15

then : 0.65^z=740
Divide each expression in the equation by 4000.
0.65^z=7004000

Answer 16

What are you doing man..
You are insulting me.. :P

Answer 17

^

Answer 18

then : 0.65^z=740
Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln(0.65^z)=ln(740)

Answer 19

\(\color{blue}{\text{Originally Posted by}}\) @Howard-Wolowitz
ok fine here: Remove parentheses around 0.65.
4000⋅0.65z=700
Divide each term in the equation by 4000.
\(\color{blue}{\text{End of Quote}}\)
here we go1!!!!

Answer 20

what do you mean?

Answer 21

wont me to stop

Answer 22

How you get 740 on right side?

Answer 23

\(\color{blue}{\text{Originally Posted by}}\) @Howard-Wolowitz
ok fine here: Remove parentheses around 0.65.
4000⋅0.65z=700
Divide each term in the equation by 4000.
\(\color{blue}{\text{End of Quote}}\)
you can't just remove the parentheses :(

Answer 24

@radar am I correct with D

Answer 25

its not 740 its 7/40

Answer 26

The logarithm of a product is equal to the sum of the logarithms of each factor (e.g.log(xy)=log(x)+log(y)). The logarithm of a division is equal to the difference of the logarithms of each factor (e.g.log(xy)=log(x)−log(y)).
−0.43078292z=1(ln(7)−ln(40))

Answer 27

okay do mean (.65)^z or .65z ?

Answer 28

you*

Answer 29

0.65^z

Answer 30

why did you say here we go!!!!!!!

Answer 31

"4000⋅0.65z=700
Divide each term in the equation by 4000."
okay so here it should be (.65)^z
right ?

Answer 32

0.65^z=740

Answer 33

THEN : Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln(0.65^z)=ln(740)

Answer 34

and how did you get 740 ?

Answer 35

i didnt i got 7/40

Answer 36

\(\color{blue}{\text{Originally Posted by}}\) @Howard-Wolowitz
0.65^z=740
\(\color{blue}{\text{End of Quote}}\)
that's why i asked

Answer 37

oh I see .. well thats because I typed it wrong

Answer 38

yes right
convert 7/40 into decimal
and then take ln both side right!

Answer 39

yes

Answer 40

sorry I got lost

Answer 41

take ln both side \[\huge\rm ln(.65)^z = \ln(.175)\]
and then apply log properties

Answer 42

power rule \[\large\rm ln x^y = y \ln x\]
this one

Answer 43

now divide both side by ln .65
then you would get an answer