Question

Can someone check my answer for this problem?

Answer 1

\[\frac{ x }{ x^2-1 } - \frac{ 2 }{ x+1 }\]

Answer 2

I got \[\frac{ x-2 }{ x^2-1 }\]

Answer 3

hint:
we can rewrite your expression as follows:
\[\Large \begin{gathered}
\frac{x}{{{x^2} - 1}} - \frac{2}{{x + 1}} = \hfill \\
\hfill \\
= \frac{x}{{\left( {x - 1} \right)\left( {x + 1} \right)}} - \frac{2}{{x + 1}} \hfill \\
\end{gathered} \]

Answer 4

the least common multiple between the denominators, is (x-1)(x+1)

Answer 5

so we get:
\[\Large \frac{x}{{\left( {x - 1} \right)\left( {x + 1} \right)}} - \frac{2}{{x + 1}} = \frac{{x - 2\left( {x - 1} \right)}}{{\left( {x - 1} \right)\left( {x + 1} \right)}} = ...?\]

Answer 6

please continue

Answer 7

Would my answer be right? it makes sense to me.

Answer 8

I got this result:
\[\Large \begin{gathered}
\frac{x}{{\left( {x - 1} \right)\left( {x + 1} \right)}} - \frac{2}{{x + 1}} = \frac{{x - 2\left( {x - 1} \right)}}{{\left( {x - 1} \right)\left( {x + 1} \right)}} = \hfill \\
\hfill \\
= \frac{{x - 2x + 2}}{{{x^2} - 1}} = \frac{{2 - x}}{{{x^2} - 1}} \hfill \\
\end{gathered} \]

Answer 9

ahh so the x and the 2 would be switched around. There isn't an option for that x-2 and -x+2

Answer 10

what are your options, please?

Answer 11

one second

Answer 12

\[1. \frac{ x-2 }{ x^2-1 } 2.\frac{ -x+2 }{ x^2-1 } 3.\frac{ -x-1 }{ x^2-1 }4.\frac{ x-4 }{ x^2-1 } \]

Answer 13

ok! As you can see, the right answer is the second option

Answer 14

since 2-x= -x +2

Answer 15

ahhh I got it, thanks for all your help!

Answer 16

thanks! :)