x+38x=y2+12 24x-64=12
@dan815 can you help me?
@amistre64
statement ?
Hello I am qualified helper reporting for duty
Thanks! :D
x+38x=y2+12 24x-64=12 can you make this more clear, are these supposed to be exponents
\[x+38^x=y^2+12\\ 24x-64=12\] something like this?
nope. No exponents. It looks like this. \[x+38x=y2+12\] \[24x-64=12\]
Would I subtract 38x from both sides to get x by itself.
Because I asked a Qualified Helper.
What do you need help with? I'm not sure what you need
okay so in that case simple add all the like terms you see in the equation first
simply*
then would it just be 38x=y2+12?
because you add x+38x?
39*x
\[39x\] ?
\[Equation~1\\39x=2y+12\\ \\ \\ Equation~2\\ 24x-64 + 64=12+64\\ 24x=76\\ x=76/24\]
ohhh. Thank you!
now do I plug 76/24 in for every x I see in equation 2?
\(\color{blue}{\text{Originally Posted by}}\) @k_lynn \[39x\] ? \(\color{blue}{\text{End of Quote}}\) \[\large\rm \color{red}{1}x+38x\] yes there is invisible one so (1+38)x =39x :-)
Yes that's is right, now you can solve for y, as you know what x is: x=76/24 \[39*x=2y+12\\ 39*\color {red}{(76/24)}=2y+12\\ 39*76/24 \color {red} {-12} = 2y+12\color {red}{-12}\\ \frac{(39*76/24-12)}{\color {red}{2}}=\frac{2y}{\color {red}{2}}\\ y=\frac{(39*76/24-12)}{{2}}\]
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