A Standing wave. Trig help!
I am trying to find an example in my book, one moment.
Ok :)
hmm, my book says: "If there are two waves traveling along the same string, then the movement of the string is determined by the sum of the two waves. For example, if the string is attached to a wall, then the waves bounce back with the same amplitude and speed but in the opposite direction. In this case, one wave is described by y=A sin K (x-vt) and the reflected wave by y= A sin K(x+vt). The resulting wave is y(x,t)=A sin k(x-vt)+ A sin k(x+vt) [add the two waves] =2A sin kx cos kvt
[sum-to-product formula] is the second =
lets look at one wave y(x,t)= 7 sin (1/2 ( x - vt ) )
A would be 7 because that is the amplitude of the wave
not sure how to eliminate v
I'd the period is 4π then the frequency is 1/4π. β=ω = 2πf = 1/2
Wait the problem says the period is 4pi but the picture shows it as pi
Sinαx = 0 when x=0,π/2 &π so α=2
The graph is for y&x
and alpha = k?
the given period is 4pi so I would do 2pi/k = (2pi)/(4pi) and the period ends up being 1/2?
I'm still confused as to why they say the period is 4pi if it's pi in the pic o_0
im going to come back to this, be right back
k
@zepdrix I promise I dont' know how to do this one. xD
If you're at all familiar with the graph of the sine wave, you can immediately remove the cosine factor by setting \(\beta=0\). As someone mentioned above, \(A=7\) guarantees an amplitude of \(7\). As for the period, you're right, it's \(\pi\), which means \(\alpha\) should satisfy \(\dfrac{2\pi}{\alpha}=\pi\).
Then again, that's the period if you just refer to the graph and not the given information.
That info could amount to a typo. If the nodes are as listed (and they agree with the graph), then the period is indeed \(\pi\), not \(4\pi\).
hm, ok :)
so, so far I have y= 7sin(ax)cos(beta(t)) how do I fill in all that?
@SithsAndGiggles
@FibonacciChick666
Sorry, trig was 10th grade(8ish years ago).... I don't remember that.
aw man haha, well thanks anyway.
I've already given you the values for α and β!
^^ thanks alekos. I didn't see that before, oopsies.
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