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Calculus1
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OpenStudy (anonymous):
How would I find the length of the curve?
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OpenStudy (anonymous):
Find the length of the curve defined by\[y=x^{3/2}\] from x=0 to x=4. I keep getting 3 but I think it's wrong.
OpenStudy (zarkon):
why don't you show what you tried
OpenStudy (anonymous):
\[\int\limits_{0}^{4}\sqrt{1+\frac{ (3\sqrt{x})^2 }{ (2)^2 }}\] For some reason it wont let me show the whole thing squared
OpenStudy (anonymous):
\[\int\limits_{0}^{4}1+\frac{ 3\sqrt{x} }{ 2 }\] and I got 3
OpenStudy (zarkon):
that last line is not correct
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OpenStudy (zarkon):
\[\sqrt{1+a^2}\neq 1+a\]
OpenStudy (anonymous):
but sqr(1) = 1
OpenStudy (zarkon):
so
OpenStudy (zarkon):
for example
\[\sqrt{1+2^2}=\sqrt{5}\]
\[1+2=3\]
\[\sqrt{5}\neq 3\]
OpenStudy (anonymous):
Then is it \[\sqrt{10}-1?\]
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OpenStudy (anonymous):
for the answer
OpenStudy (zarkon):
no
OpenStudy (anonymous):
But wouldn't it be \[\int\limits_{0}^{4}\sqrt{1+\frac{ 9x }{ 4 }}\]?
OpenStudy (zarkon):
dx.....yes
OpenStudy (anonymous):
ohh i forgot to integrate
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OpenStudy (anonymous):
How do I deal with the square root sign when it comes to immigration?
OpenStudy (anonymous):
integration*
OpenStudy (zarkon):
u-substitution
OpenStudy (anonymous):
oh yeahh
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