Ask your own question, for FREE!
Calculus1 22 Online
OpenStudy (anonymous):

How would I find the length of the curve?

OpenStudy (anonymous):

Find the length of the curve defined by\[y=x^{3/2}\] from x=0 to x=4. I keep getting 3 but I think it's wrong.

OpenStudy (zarkon):

why don't you show what you tried

OpenStudy (anonymous):

\[\int\limits_{0}^{4}\sqrt{1+\frac{ (3\sqrt{x})^2 }{ (2)^2 }}\] For some reason it wont let me show the whole thing squared

OpenStudy (anonymous):

\[\int\limits_{0}^{4}1+\frac{ 3\sqrt{x} }{ 2 }\] and I got 3

OpenStudy (zarkon):

that last line is not correct

OpenStudy (zarkon):

\[\sqrt{1+a^2}\neq 1+a\]

OpenStudy (anonymous):

but sqr(1) = 1

OpenStudy (zarkon):

so

OpenStudy (zarkon):

for example \[\sqrt{1+2^2}=\sqrt{5}\] \[1+2=3\] \[\sqrt{5}\neq 3\]

OpenStudy (anonymous):

Then is it \[\sqrt{10}-1?\]

OpenStudy (anonymous):

for the answer

OpenStudy (zarkon):

no

OpenStudy (anonymous):

But wouldn't it be \[\int\limits_{0}^{4}\sqrt{1+\frac{ 9x }{ 4 }}\]?

OpenStudy (zarkon):

dx.....yes

OpenStudy (anonymous):

ohh i forgot to integrate

OpenStudy (anonymous):

How do I deal with the square root sign when it comes to immigration?

OpenStudy (anonymous):

integration*

OpenStudy (zarkon):

u-substitution

OpenStudy (anonymous):

oh yeahh

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!