If (-3, y) lies on the graph of y = 3^x, then y =
1/27
-1
-27
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OpenStudy (adi3):
wht do u think
OpenStudy (anonymous):
1/27 ?
OpenStudy (adi3):
How did u do it
OpenStudy (anonymous):
I didn't..lol educated guess
OpenStudy (adi3):
where the graph
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OpenStudy (adi3):
where is the graph
OpenStudy (adi3):
do u hve the graph
OpenStudy (anonymous):
There is no graph.
OpenStudy (sepeario):
i'm guessing you have to substitute values for x and y?
OpenStudy (anonymous):
Idk. That's literally all the question says.
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OpenStudy (skullpatrol):
y = 3^(-3)
OpenStudy (sepeario):
\[y=3^{-3}\]
OpenStudy (sepeario):
hence y = 1/27
OpenStudy (anonymous):
That's not one of the answer choices.
OpenStudy (sepeario):
haha, but you have to evaluate 3 to the power of -3!
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OpenStudy (anonymous):
So it's 1/27 ..? Lol that's what my guess was.
OpenStudy (skullpatrol):
a^(-n) = 1/a^n
OpenStudy (anonymous):
@Sepeario
OpenStudy (sepeario):
yes?
OpenStudy (anonymous):
It is 1/27 ..?
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OpenStudy (sepeario):
yes, as @skullpatrol stated due to the evaluation of exponents.
OpenStudy (anonymous):
Thanks y'all! :-)
OpenStudy (skullpatrol):
$$\Huge a^{-n}= \dfrac{1}{a^n}$$
OpenStudy (skullpatrol):
Thanks for asking :)
OpenStudy (phi):
in case it's not obvious:
you can invert a number to remove the negative exponent
\[ 3^{-3} = \frac{1}{3^3} \]
and remember that \(3^3 \) means \(3 \cdot 3 \cdot 3\)
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