Question

Help with Pascal Principle

Answer 1

first piece of tape what it was before the mass went in. The higher piece was what it was after it was added.

Answer 2

@Data_LG2

Answer 3

hello :)

I think this part of your lab is related to archimedes principle not pascal...

anyway, have you calculated the volume displacement of the water?

Answer 4

Rip I think so too sorry I just learned about both so its like ><

Answer 5

Oh wait. It legit just says "achimedes principle

Answer 6

im blind lol

Answer 7

It's okay, you'll learn it better soon ^-^
Pascal's principle has something to do with liquid pressure in an enclosed system.
Archimedes principle: buoyant force = weight of displaced fluid (remember this because you'll use this in the future )

Now with your lab...
Some information that you'll need:

density of water is \(\sf 1000 kg•m^{-3}\)
acceleration due to gravity \(\sf 9.8 m•s^{-2}\)

density formula is mass over volume: \(\sf \rho = \large \frac{m}{V}\), where V is the volume displacement.

Tell me the difference between the volumes in your lab. (Subtract those two values: the volume before - volume after)

Answer 8

so in the picture its at 200 before and 300 after. so the change is 100

Answer 9

or i guess before-after = -100

Answer 10

are you sure it's 300 not 302 ml ?

displacement is always after - before :)

Answer 11

I guess the tape does go past 300 but I am unsure the measurement though. because it looks like its going up by 5

Answer 12

But I counted every line it would be short before you hit 350

Answer 13

S: evil measurements ><

Answer 14

lol it is the standard measurement in any measuring instruments.
long lines have the 0, 5, 10, 15, 20 ...
short lines always count from 1 to 4

Answer 15

Ah I just suck then

Answer 16

nah you're not :)

alright then so we'll assume that it is 302, and 200, so Vd will be?

Answer 17

200-302=-102?

Answer 18

displacement is always after - before :)

Answer 19

Lel rip above like before the measurements happened you said before - after so then positive 102

Answer 20

1000=m/102?

Answer 21

^_^ okay good. We'll need that value later.

Now, we'll find the mass of the water using the density formula.
Yes! that's right !

Answer 22

but wait.. the units are different. you have to convert units first.

Answer 23

Vd= 102 ml (this is in milliliters)

p= 1000 kg/m^3 (this is in meters cube)

Answer 24

Welp we have to change it to kg per liter right?

Answer 25

to make it easier, just change 102 ml to m^3 because if you'll convert kg/m3 to kg/L, you'll also have to convert ml to L :)

Answer 26

0.000102 m^3?

Answer 27

yep. now use the formula to calculate for the mass