Help with Finding the Angle Between Two Lines
Find the angle between the following two lines: 2x + 3y = 5 x − 3y = 6
3y=-2x+5 y=(-2x+5)/3 y=-2/3x + 1.7 3y=-x+6 y=(-x+6)/3 y=-1/3+2
tan^-11(-2/3) 180+tan^-1(-1/3) @freckles does this look right so far?
ok I'm here finally after constant loading
one sec let me look at your problem
-33.7 180+-18.4
161.6-(-33.7)
also i meant ^-1 not -11
2x + 3y = 5 x − 3y = 6 ======= 3y=-2x+5 y=-2/3*x+5/3 x-3y=6 -3y=-x+6 y=1/3*x-2 and let's see also where do they intersect 1/3*x-2=-2/3*x+5/3 x-6=-2x+5 x+2x=5+6 3x=11 x=11/3 so @x=11/3 we have y=1/3*11/3-2=11/9-2=(11-18)/9=-7/9 so the intersection is (11/3,-7/9) so this graph looks like this: |dw:1431471596444:dw| so which angle are we talking about I wonder
oh dang it... I didnt cancel the negatives in the second one
or multiply them properly more so lol
|dw:1431471752688:dw| I think I will look here and see if I can find those two angles at the intersection of both of those right triangles
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