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Mathematics 23 Online
OpenStudy (darkbluechocobo):

Help with Finding the Angle Between Two Lines

OpenStudy (darkbluechocobo):

Find the angle between the following two lines: 2x + 3y = 5 x − 3y = 6

OpenStudy (darkbluechocobo):

3y=-2x+5 y=(-2x+5)/3 y=-2/3x + 1.7 3y=-x+6 y=(-x+6)/3 y=-1/3+2

OpenStudy (darkbluechocobo):

tan^-11(-2/3) 180+tan^-1(-1/3) @freckles does this look right so far?

OpenStudy (freckles):

ok I'm here finally after constant loading

OpenStudy (freckles):

one sec let me look at your problem

OpenStudy (darkbluechocobo):

-33.7 180+-18.4

OpenStudy (darkbluechocobo):

161.6-(-33.7)

OpenStudy (darkbluechocobo):

also i meant ^-1 not -11

OpenStudy (freckles):

2x + 3y = 5 x − 3y = 6 ======= 3y=-2x+5 y=-2/3*x+5/3 x-3y=6 -3y=-x+6 y=1/3*x-2 and let's see also where do they intersect 1/3*x-2=-2/3*x+5/3 x-6=-2x+5 x+2x=5+6 3x=11 x=11/3 so @x=11/3 we have y=1/3*11/3-2=11/9-2=(11-18)/9=-7/9 so the intersection is (11/3,-7/9) so this graph looks like this: |dw:1431471596444:dw| so which angle are we talking about I wonder

OpenStudy (darkbluechocobo):

oh dang it... I didnt cancel the negatives in the second one

OpenStudy (darkbluechocobo):

or multiply them properly more so lol

OpenStudy (freckles):

|dw:1431471752688:dw| I think I will look here and see if I can find those two angles at the intersection of both of those right triangles

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