Question

You are given 100 Ω resistors.
A. If in a series Rtotal=
B. If in parallel Rtotal=

Answer 1

two resistors?

Answer 2

\[R_{total_{series}} = R_1 + R_2 + R_3 + \cdots\]
\[\frac{1}{R_{total_{para}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \cdots\]

Answer 3

in series, resistances add: \(R_{total}=\sum_i R_i\)
in parallel, *conductances* (or inverse resistances) add: \(G_{total}=\sum_i G_i\) where \(G=1/R\) so \(\dfrac1{R_{total}}=\sum_i\dfrac1{R_i}\)

Answer 4

So um what do you to know it? I only know it by

Rtotalseries=R1+R2+R3+⋯

1Rtotalpara=1R1+1R2+1R3+⋯

Answer 5

Since we don't know how many resistors we have, let's just say we have N of them (that covers the bases). Each one is at 100, so
Rtotalseries = 100 + 100 + 100 (N times) or = N(100)
1/Rtotalpara = 1/100 + 1/100 + 1/100 (N times) or = N(1/100) = N/100
so, Rtotalpara = 100/N.

Answer 6

Oh so if it was 4 resistors then what?

Answer 7

they gave you the formulas