For an endothermic reaction, how will the value for Keq change when the temperature is increased?
a) Keq is not effected by temperature. b) Keq will decrease. c) Keq will increase. d) It will be reduced by half. I know it's either B or C .
since the reaction is endothermic, "heat" is treated just like a \(reactant\), so it will follow the same rules of shifting equilibrium
I understand that because the temp is increased it will shift towards the product. I just don't know if that means Keq will increase or decrease?
I think the answer is C ?
@aaronq @amistre64 do you guys know?
Here's a hint: \(K_{eq}\) is the equilibrium constant, the ratio of the products to reactants. \(\sf K_{eq}=\dfrac{[products]}{[reactants]}\)
I understand all that. I know that when the temp increases Keq is shifted towards the products. I just don't know weather or not that means Keq will increase or decrease?
I'll make it more obvious. if initially at given temperature, [products]=1 and [reactants]=1, then \(\sf K_{eq}=\dfrac{[products]}{[reactants]}=\dfrac{1}{1}=1\) at a higher temp [products]=1.5 and [reactants]=0.5, then \(\sf K_{eq}=\dfrac{[products]}{[reactants]}=\dfrac{1.5}{0.5}=3\)
thank you! It is C, correct? hahah, I thought it was C.
yeah. next time try to use numbers, it makes things clearer
no prob by the way
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