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Mathematics 21 Online
OpenStudy (horsegirl27):

Help me please!! Medal and fan I need help ASAP!!!!!!!!!!

OpenStudy (horsegirl27):

http://prntscr.com/74w6rl I have tried but make mistakes and nothing is working out and I'm confused and really need help fast.

OpenStudy (horsegirl27):

@rational please help me!!!!!!

OpenStudy (horsegirl27):

@sleepyjess can you help?

OpenStudy (horsegirl27):

@mathmate @mathmath333

OpenStudy (mathmate):

Do you know what the key-words mean? - consistent -inconsistent -dependent -independent

OpenStudy (mathmate):

Knowing the definition of the terms is a big step in solving a problem!

OpenStudy (horsegirl27):

Yes, I do understand the words

OpenStudy (anonymous):

do u need help

OpenStudy (anonymous):

@mathmate is right you actually must know the definition first to be able to answer this question..

OpenStudy (anonymous):

Consistent is when two lines have (at least) 1 solution and inconsistent is when there is no solution at all and when you add dependent and independent it means when two lines cross each other like this: |dw:1431607543829:dw|

OpenStudy (anonymous):

independent literally means the two lines don't depend on each and they just happen to cross each other (and if that cross or intersection happens ONLY ONCE it means it is independent)

OpenStudy (anonymous):

if two lines are literally on top of each other both lines are having the exact coordinates in any given point of the line, then that means the lines are dependent on each other

OpenStudy (anonymous):

This is the two lines in system 1 you can see that the two lines are intersecting at a point, so this is consistent, but since it's happening only at 1 particular point, these two lines are independent

OpenStudy (anonymous):

This is system two, since the graph is not only parallel but also literally on top of each other which means it's having countless of places where the two lines are having same exact coordinates, therefore it is consistent as well as dependent.

OpenStudy (anonymous):

try doing system 3 on your own you can check out your graph on Desmo https://www.desmos.com/calculator

OpenStudy (horsegirl27):

Thank you!

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