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Mathematics 18 Online
OpenStudy (anonymous):

What is the length of QR to the nearest hundredth of a centimeter? _____cm

OpenStudy (anonymous):

OpenStudy (anonymous):

You're gonna want to use the law of sines. Should we go over that again? :)

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

So the sin of an angle over the opposite length is going to be equal to the sin of any other angle over the length. So in this problem we have a length of 12.38 opposite to a sin of 90. That is going to be equal to the length of QR over sin 49. The equation would look like this\[\frac{ 12.38 }{ \sin(90) }=\frac{ x }{ \sin(49) }\] Now all you have to do is get x alone.

OpenStudy (anonymous):

sin(49)(12.38) = sin(90)x 606.62 = 90x x = 6.74

OpenStudy (anonymous):

is that right? o.o

OpenStudy (anonymous):

Well sin(90) is always equal to 1. So 12.38/sin(90) = 12.38. So just multiply 12.38 by sin(49) to get 9.34.

OpenStudy (anonymous):

I see

OpenStudy (anonymous):

You get x alone by doing\[\frac{ 12.38 }{ \sin(90) }=\frac{ x }{ \sin(49) }\to \sin(49)*\frac{ 12.38 }{ \sin(90) }=x\]

OpenStudy (anonymous):

I forgot to find out what sin(90) and sin(49) equals because I didn't use the right calculator and thought I could just cancel it out.

OpenStudy (anonymous):

sin(90)=1 and sin(49)=.754

OpenStudy (anonymous):

kk Thanks~

OpenStudy (anonymous):

No problem :)

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