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find the area of the region bounded by the functions f(x)=-x^2 +9x-4, x=-1, x=2, and y=0
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x=-1. are you sure it isn't x=1?
yes im sure it is x=-1
i don't think there can be an area if y=0
that is why was not sure. so the answer is no area?
maybe, if you were not given that value however, you would integrate with the x values acting as limits.
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thank you
\[\begin{align*}f(x)&=-x^2+9x-4\\\\ &=-\left(x^2-9x\right)-4\\\\ &=-\left(x^2-9x+\frac{81}{4}-\frac{81}{4}\right)-4\\\\ &=-\left(\left(x-\frac{9}{2}\right)^2-\frac{81}{4}\right)-4\\\\ &=-\left(x-\frac{9}{2}\right)^2+\frac{81}{4}-4\\\\ &=-\left(x-\frac{9}{2}\right)^2+\frac{65}{4} \end{align*}\] |dw:1431574649764:dw| There's definitely an area...
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