Question

if f(x) = 2/x^2, find f'(5)?

Answer 1

Do f(5) = 2/5^2.

Answer 2

already tried it, its wrong

Answer 3

f' not f

Answer 4

f prime of 5, its f'(5)

Answer 5

what does f "prime" mean??

Answer 6

2/5^2.

Answer 7

hint: \(\bf \cfrac{2}{x^2}\iff 2x^{-2}\)

Answer 8

i was about to right the same thing lol @jdoe0001

Answer 9

do i do the derivative of that? @jdoe0001

Answer 10

@_alex_urena_ that's what the f' <-- prime means, as Loser66 hinted

Answer 11

@xapproachesinfinity that simply means i need to get a tinfoil hat, so you can read my mind =P

Answer 12

i mean -2/3(x)^3

Answer 13

well, 2 * -2 = -4
otherwise the exponent is correct

Answer 14

you can, you can't read me rather =|

Answer 15

\(\bf \cfrac{d}{dx}[ 2x^{-2}]\implies -4x^{-3}\implies \cfrac{-4}{x^3}\)

Answer 16

oh ok i get you, i was doing something else

Answer 17

so now do i plug in the 5? @jdoe0001