I need a explanation to these:

Question

howard-wolowitz · Answer

For the first one: A(x-5)+1(x-4)=-x+6
A(x-5)+x-4=-x+6
A(x-5)=-2x+10

now plug in x=6

anonymous · Answer

expain what? i.e. what are you trying to do? 
is this partial fraction decomposition?

howard-wolowitz · Answer

I know how to work these two! i got as far as that ^

howard-wolowitz · Answer

*dont know how

howard-wolowitz · Answer

and yes these are partial functions... if thats what their called

anonymous · Answer

you got this far 
$$A(x-5)=-2x+10$$ right?

howard-wolowitz · Answer

yes

anonymous · Answer

you could 
a) distribute on the right and get $Ax-10=-2x+10$ which means $A=-2$ be equating the coefficients

anonymous · Answer

or you could 
b) factor on the left and get 
$$A(x-5)=-2(x-5)$$ from which you see $A=-2$ with your eyeballs

anonymous · Answer

lol i meant "distribute on the left" or 
"factore on the right"
got those backwards sorry b

howard-wolowitz · Answer

I do see with my eyeballs. lol.. and I"ll try both ways. Thanks!

anonymous · Answer

damn i am full of typos
if you distribute on the LEFT you get 
$$Ax-5A=-2x+10$$

anonymous · Answer

in any case it should be clear that $A=-2$

howard-wolowitz · Answer

I gotcha, thanks you for explaining that