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Mathematics 24 Online
OpenStudy (vera_ewing):

@Jamierox4ev3r

OpenStudy (vera_ewing):

OpenStudy (vera_ewing):

I think it is D. Can you check please?

HanAkoSolo (jamierox4ev3r):

If g(n) is established as equal to 11. Positive 11

OpenStudy (♪chibiterasu):

The form for geometric sequences is: \[a_n = a_1 \times r^{n-1}\]

OpenStudy (vera_ewing):

11.100?

HanAkoSolo (jamierox4ev3r):

While that shouldn't have an affect on the geometric sequence that currently exists, (if you multiply it, you are defining it as a1

OpenStudy (vera_ewing):

Jamie, you got 11.100 ?

OpenStudy (♪chibiterasu):

The \[a_9\] does not matter. What matters is how the options are formatted. Only one of these options has the correct sequence form.

OpenStudy (♪chibiterasu):

It is not C. The first term is being multiplied, not added.

OpenStudy (vera_ewing):

Ohh so it's A?

HanAkoSolo (jamierox4ev3r):

wait chibi...how do you know if f(n) is the first term?

HanAkoSolo (jamierox4ev3r):

it's been a while since I've actually worked with the formulas, though i do remember the overarching concepts

OpenStudy (♪chibiterasu):

\[a_n = a_1 × r^{n−1}\] They are asking to find \[a_n\] This is the geometric sequence in which the first term (f(n)) is multiplied.

OpenStudy (♪chibiterasu):

We know it will be geometric since it tells us so. If we added a_1, it wouldn't be a geometric sequence.

OpenStudy (vera_ewing):

So the answer is A?

OpenStudy (♪chibiterasu):

The first term is being multiplied into \[a^{n-1}\] Not into just a. It will not be in parenthesis.

Miracrown (miracrown):

For a geometric sequence, we won't have any terms that are added or subtracted In choice a, 11 is raised to the n-1 power, while it was not raised to that power in the original f(n) function

OpenStudy (vera_ewing):

Okay so it's B?

OpenStudy (♪chibiterasu):

Yeah.

Miracrown (miracrown):

YES

Miracrown (miracrown):

:)

OpenStudy (vera_ewing):

Thank you.

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