Question

Discrete random distributions !

Answer 1

Find the distribution law for:
1. The number of girls in a family of six kids, knowing that the probability of birth of a girl is 0.51.
2. The annual number of accidents at an intersection, knowing that every day is 1/125 chance of accident:
3. In a group of 20 people, including 5 women, the number of women of a delegation of 6 guests.
4. how many times have launched a dice to get twice six.
5. The number of people presenting a date for a consultation disease.
6. Number of replies yes or no to a question of a survey.

Answer 2

1.Binomial
2.Binomial
I need help with the rest of this.

Answer 3

number 3, has 5 women ?

Answer 4

15 men

Answer 5

I think this is called a hypergeometric distribution

Answer 6

@perl You're right.

Answer 7

my guess is that 4 is binomial with negative exponent

Answer 8

In general a hyper-geometric distribution is:
$$\Large P(X=k) = {{{K \choose k} {{N-K} \choose {n-k}}}\over {N \choose n}}
$$ here we have
$$\Large P(X=k) = {{{5 \choose k} {{15} \choose {6-k}}}\over {20 \choose 6}}
$$

Answer 9

its either geometric distribution or

Answer 10

3 is hyper I'm very sure of this.
4 is doubtly binomial with neg exp.

Answer 11

the geometric distribution is a type of negative binomial distribution, so negative binomial works

Answer 12

brb