The population (in millions) of a certain country can be approximated using the following function;
P(x)=40 ( 1.02)^x
where x is the number of years after 2000. which of the following calculations will tell you what the population can be expected to reach 200 million?
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OpenStudy (zmtgaminghd):
279,378
OpenStudy (cutiecomittee123):
oh well there are options
ln(5/1.02)
ln(5)/ln(1.02)+2000
ln(5/1.02)+2000
ln(5)/ln(1.02)
OpenStudy (campbell_st):
ok so let P(x) = 200
so
\[200 = 40\times (1.02)^x\]
divide both sides of the equation by 40
\[5 = (1.02)^x\]
take the log of both sides... and apply the log law for powers
and you'll get the answer
OpenStudy (campbell_st):
the log law for powers is
\[\log(x^a) = a \times \log(x)\]
OpenStudy (cutiecomittee123):
so log(5)=log(1.02)^x ??
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OpenStudy (campbell_st):
yes... so now what happens to x, with you use the log law for powers
OpenStudy (cutiecomittee123):
can you show me how that works?
OpenStudy (campbell_st):
ok
\[\log(5) = x \times \log(1.02)\]
now you can solve for x
OpenStudy (cutiecomittee123):
got it! so just divide log(5) by log(1.02)
OpenStudy (campbell_st):
that's correct
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OpenStudy (cutiecomittee123):
so the answer is d, in the options i have above?
OpenStudy (campbell_st):
yes
OpenStudy (cutiecomittee123):
Can you help me with another one?
OpenStudy (cutiecomittee123):
@campbell_st
OpenStudy (campbell_st):
just post a new question, there are lots of people who can help, I'll look at it if I have time
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