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Mathematics 18 Online
OpenStudy (darkbluechocobo):

Help with ellipses

OpenStudy (darkbluechocobo):

Find the equation of the following an ellipse based on the following information: Foci: (0, 0), (0, 8), Major axis of length 16, and a minor axis of length 4.

OpenStudy (darkbluechocobo):

so you can find a and b by dividing 16/2 and 4/2 which: a=8 b=2

OpenStudy (darkbluechocobo):

so our equation would look like; \[\frac{ (x-h)^2 }{ 8^2 }-\frac{ (y-h)^2 }{ 2^2 }=1\]

OpenStudy (phi):

ok, but the focuses lie on the major axis

OpenStudy (darkbluechocobo):

Would that affect a and b?

OpenStudy (phi):

1) the center will be at the mid-point between the two foci (so find the average of the two). 2) you add the two terms (you show subtraction... I think that is a hyperbola) 3) the major axis lies on the y axis (because foci (0,0) and (0,8) lie on the y axis) that means the "a" goes with the y term

OpenStudy (darkbluechocobo):

oh I screwed up the equation T_T. It is a plus

OpenStudy (darkbluechocobo):

the mid point would be 4 and y = 8 as well ?

OpenStudy (phi):

if you plot (0,0) and (0,8) where is the mid point? by counting you can see (0,4) that is the center (h,k). i.e. use h=0 and k=4 in your equation

OpenStudy (darkbluechocobo):

Oops i meant (0,4) not just 4 sorry.

OpenStudy (darkbluechocobo):

\[\frac{ x^2 }{ 8^2 }+\frac{ (y-4)^2 }{ 2^2 }=1\]

OpenStudy (darkbluechocobo):

@phi does this look correct?

OpenStudy (phi):

except the 8^2 goes with the y (because the major axis is on the y-axis, and the major axis is always the bigger number)

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