Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

I have a confusing Algebra assignment I really do not understand, it is decently long. Any help would be appreciated!

OpenStudy (anonymous):

OpenStudy (anonymous):

@phi Please help me out!

OpenStudy (anonymous):

@jigglypuff314

TheSmartOne (thesmartone):

@jigglypuff314 @sleepyhead314 QH help :)

OpenStudy (anonymous):

If anyone is actually looking at this, for the first part asking for f(x), I got the equation x(1.1)^3-1, I don't know if this is correct or not.

OpenStudy (phi):

the exponent should be x. the leading number (where you have x) should be between 2 and 12

jigglypuff314 (jigglypuff314):

Hello and Thank you for asking a Qualified Help question ^_^ Might I ask what point you tried using? :)

OpenStudy (anonymous):

You are right Phi, my bad, It should be 3(1.1) ^ x-1 (3 being my number I chose between 2-12) is that correct?

OpenStudy (phi):

yes. as a check, when x is 1, you get 3 * 1.1^0 but 1.1^0 is 1 (anything to the zero power is 1) and you get 3*1 or 3 so the first day you get 3

OpenStudy (anonymous):

That makes sense, so the answer to Create the exponential function, f(x), that represents the number of packing peanuts found on the beach each day would be 3(1.1)^x-1

OpenStudy (phi):

yes. though I would put in parens, like this f(x) = 3(1.1)^(x-1)

OpenStudy (anonymous):

Okay thank you, that's what I put. I can do the graphing myself. But there are 5 other parts to this question, now I know thats a lot, but do you think you would be able to help me with the rest of this assignment?

OpenStudy (anonymous):

@phi

OpenStudy (phi):

the next part is graph the line v(x)

OpenStudy (anonymous):

Yes correct, it says to use the function v(x) = 1/4x + 14, I thinkk I would plug in 3 as X?

OpenStudy (phi):

to plot a curve, you find points on the curve i.e. pick an x, and find the y using the equation. but with a line, you only need two points, and draw a straight line through them

OpenStudy (phi):

I would use x=0 (easy to do) and x=4 (because 4/4 is a nice integer)

OpenStudy (phi):

the exponential is more painful. It is not straight, and you will get fractions.

OpenStudy (phi):

maybe you can use geogebra or other software

OpenStudy (anonymous):

so it would then look like: 1/4(0) + 14 = 14 1/4(4) + 14 = 15 is that right? or am I completely butchering that.

OpenStudy (phi):

yes, so two points on v(x) line are (0,14) and (1,15)

OpenStudy (anonymous):

so I've plotted that, would that be correct?

OpenStudy (phi):

the first number (x value) is the day. you did it backwards

jigglypuff314 (jigglypuff314):

careful! (x, y) x would be how much left or right and y is how much up or down :)

OpenStudy (phi):

and after you plot the two points, draw a line through them

OpenStudy (anonymous):

Ah okay, i see what I did there. Let me fix that.

OpenStudy (anonymous):

Okay, so when they ask Explain what the solution means in terms of ecological crisis, would it be that the amount of volunteers helping to clean up the packing peanuts does not suffice to the amount of packing peanuts found on the beach?

OpenStudy (phi):

If you plot the line v(x) and the exponential curve f(x), you will see that v(x) is "above" f(x) but at around day 20 or 21, f(x) goes above v(x). that means for the first 20 days, the clean up stays ahead of the problem. But after day 20, the pollution comes faster than they can take it away

OpenStudy (anonymous):

This is what I put, I am trying to say this stuff in my own words! When looking at the graph, f(x) is the exponential curve, and one can see that v(x) falls above f(x). From that, one can see that during days 20 and 21, f(x) goes above v(x), meaning that until the first 20 days, volunteers clean the packing peanuts up faster than they litter the ground, after that, the pollution arrives faster than the volunteers can clean up.

OpenStudy (phi):

yes. but you should show how you know the curves where the curves cross. in other words, solve for x, from \[ \frac{1}{4} x +14 = 3 \cdot (1.1)^{x-1} \]

OpenStudy (anonymous):

Okay, I will, thank you! Let me take a picture of part two now, this is such a long assignment I'm sorry!

OpenStudy (anonymous):

OpenStudy (phi):

btw, here is the graph for part I

OpenStudy (phi):

There is no easy way to solve the ugly equation I posted up above, but we can read off the graph the point where the curve and line cross.

OpenStudy (anonymous):

Yes, that is exactly what I need, thank you!

OpenStudy (anonymous):

So looking at the next question, it asks to create a sine function t(x) that represents the tide, I believe it would be 3 sin (pi/3x) + 4 ????

OpenStudy (anonymous):

because 3x would be the 3 feet from normal high or low

OpenStudy (phi):

ok, but why add 4?

OpenStudy (anonymous):

no wait, I mean add 3, because that is the number of packing peanuts I started with. I think, sine questions confuse me.

OpenStudy (phi):

they just want a sin for the tide (no peanuts)

OpenStudy (phi):

so t(x) = 3 sin( stuff)

OpenStudy (anonymous):

So would that mean I would choose a number for the normal tide???

OpenStudy (phi):

I would pick 0 for the "normal height" that would be someplace on the beach where the water is 0 depth at "mid-tide"

OpenStudy (phi):

next, what is the "period" of the sin wave (in hours) ?

OpenStudy (anonymous):

Okay wait so then the equation would be 3 sin + 0???

OpenStudy (anonymous):

or 3 sin (3pi/x) + 0

OpenStudy (phi):

yes, but we don't have to show adding 0

OpenStudy (phi):

now we have to fix up your 3 pi/x first step: what is the period for the tide to go one "cycle"?

OpenStudy (anonymous):

24 hours

OpenStudy (phi):

no, that is two periods hi,lo,hi,lo

OpenStudy (anonymous):

or would it be 12, because it is saying high then low, high, low

OpenStudy (anonymous):

No wait, it would be 6 hours because it is saying there are 4 tides during the 24 hours, and 24/4 = 6

OpenStudy (phi):

yes, 12 hours. They don't say if we should measure in hours or days. In part I they had x measuring days. Let's use x in days. so the period is 0.5 days we use this form: \[ \sin \left( \frac{2 \pi}{T} x\right) \] where T= 0.5

OpenStudy (phi):

one period of a sin wave looks like this|dw:1431734319200:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!