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Find the equation of the line tangent to y = –3x2 + x – 5 at x = –1.
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first find the derivative dy/dx
can you do that?
Would it be -6x+1?
yes so plug in x = -1 at this will give you the slope of the tangent
* and this
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So the slope of the tangent line would be 7 right?
yes
now you need to use the general form y - y1 = m(x - x1) where m = 7 and (x1,y1) is a point on the line use x1 = -1 and find y1 by substituting in the equation of the curve.
Would it be 2?
Would 7x-2 be my answer?
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for y1? no y1 = -3(-1)^2 - 1 - 5
Oh you get -9
y -(-9) = 7(x -(-1)) y + 9 = 7x + 7 y = 7x - 2
Okay thank you!
yw
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