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Mathematics 14 Online
OpenStudy (anonymous):

i will metal fan and give u a testimonial

OpenStudy (anonymous):

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

please help man

OpenStudy (anonymous):

I Want A Testimony!!!!

OpenStudy (michele_laino):

we have to draw your points

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

how

OpenStudy (michele_laino):

it is simple, we have touse the cartesian coordinates system

OpenStudy (michele_laino):

to use*

OpenStudy (anonymous):

i am in 7 th grade i dint know what that is

OpenStudy (michele_laino):

hint: |dw:1431796063136:dw| I havedrawn the first point, now please continue

OpenStudy (anonymous):

it is A

OpenStudy (anonymous):

now here is a tricky one

OpenStudy (anonymous):

i think it might be Y

OpenStudy (michele_laino):

Hint: we have a proportional relationship, when the subsequent formula holds: \[y = kx\] so if I substitute x=0, what is y?

OpenStudy (anonymous):

it is ether X or Y (C or D)

OpenStudy (michele_laino):

what is: \[y = kx = k \times 0 = ...?\]

OpenStudy (michele_laino):

k is a constant different to zero

OpenStudy (michele_laino):

oops.. different from 0

OpenStudy (anonymous):

right

OpenStudy (michele_laino):

so, what is \[y = kx = k \times 0 = ...?\]

OpenStudy (anonymous):

i am not sure

OpenStudy (michele_laino):

for example, if k=5 then what is: y=k*5=5*0=...?

OpenStudy (anonymous):

still not sure

OpenStudy (michele_laino):

it is simple: 5*0=...?

OpenStudy (anonymous):

0

OpenStudy (anonymous):

i still think it is c or d

OpenStudy (michele_laino):

that's right! So the point x=0, y=0, has to belong to the proportional relationship between x, and y. Namely the graph has to pass at the origin of our coordinate system. So what is the right option?

OpenStudy (anonymous):

i was right it was X

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

this one i have been stuck on for about a week

OpenStudy (anonymous):

can u manage to help me get the answer

OpenStudy (michele_laino):

here we have to determine the subsequent ratio for all of friends: \[\Large \frac{{{\text{games bowled}}}}{{{\text{number of strikes}}}}\]

OpenStudy (michele_laino):

for example for Roni, that ratio is 5/8, so please continue

OpenStudy (anonymous):

\[\frac{ 61 }{ 80 }\]

OpenStudy (anonymous):

\[\frac{ games bowled }{ number of strikes }\]

OpenStudy (michele_laino):

no, you have to compute that ratio separately for each gamer

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