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How would I go about solving this? Marco is putting some sweaters into storage for winter. He has 10 sweaters, and he can fit 6 sweaters into a box. How many different groups of sweaters can Marco pack into a box?
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@rational
10 C 6?
?
@phi
Can you help? I'm reviewing for my exam, and there's a lot I forgot..
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I think they are asking how many combinations of 6 sweaters you can pick out of 10 10 Choose 6
You have 10 sweaters/options and you only can choose 6 How many diff combinations can you have? So the formula for 10 choose 6 is ... \[\frac{n!}{k!(n-k)!}= \frac{10!}{6!4!}\] Where n are the total amt of options and k is the amt you can choose In this case n=10 and k=6
oh, that makes sense
210
yea
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thank you, I totally forgot about that
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