Write as an algebraic expression in x: sin( arctan(3/4) )
this isn't something that varies it is just a number do you mean rewrite sin(arctan(x)) as an algebraic expression in terms of x?
then use that algebraic expression to evaluate sin(arctan(x)) for x=3/4
anyways to write sin(arctan(x)) as an algebraic expression let u=arctan(x) so tan(u)=x draw a right triangle then use that triangle to find sin(u) in terms of x
sin(u)=3
that's impossible
why? tan=sin/cos, so if tan=3/4, sin=3
sin is a number between -1 and 1 so sin being 3 is very impossible
hm.
tan(u)=x is the same as tan(u)=x/1 draw a right triangle label one of the angles that isn't 90 deg u then label the opposite side x and the adjacent side 1 use Pythagorean theorem to find the hyp
then find sin(u) you will have enough info to find sin(u) since you will have opposite and hyp
how would you find sin(u) knowing only a 90 degree angle and 1 side?
you know 2 sides
the opp is x and the adj is 1 find the hyp in terms of x
use Pythagorean theorem
big hint: opp^2+adj^2=hyp^2 this is Pythagorean theorem
you have opp and adj given to you just take the square root of both sides
c=sqrt(x^2+1)
hyp is yes sqrt(x^2+1)
so you have opp is x and hyp is sqrt(x^2+1) recall sin(u)=opp/hyp
\[\sin(\arctan(x))=\frac{x}{\sqrt{x^2+1}}\]
you have now wrote sin(arctan(x)) as an algebraic expression
you can use that algebraic expression to evaluate sin(arctan(3/4))
where did the x in the numerator come from?
got it.
remember you were suppose to draw a right triangle for tan(u)=x/1 so I asked you to labeled the opposite side x and the adjacent side 1 and then I thought you used that to find the hyp
So 3/4=x/sqrt(x+1)
not sure where you got that equation i thought you wanted to evaluate sin(arctan(3/4)) remember we got sin(arctan(x)) =x/(sqrt(x^2+1)) just replace x with 3/4 to find sin(arctan(3/4))
oh!
\[\sin(\arctan(\frac{3}{4}))=\frac{\frac{3}{4}}{\sqrt{(\frac{3}{4})^2+1}} \\ \]
Is it 3/5 or 12/25? My calculator says the former, my work, the latter...
@freckles
nevermind.
Join our real-time social learning platform and learn together with your friends!