Medal A snack food is made by mixing 5lb of popcorn that cost $.80 per pound with caramel that costs $2.40 per pound. How much caramel is needed to make a mixture that costs $1.40 per pound?
You can set the equation this way: Let x = the amount of caramel required. 5%280.80%29+%2B+x%282.40%29+=+%285%2Bx%29%281.40%29 Simplify and solve for x. 4+%2B+2.40%28x%29+=+7+%2B+1.40%28x%29 Subtract 1.40(x) from both sides. 4+%2B+x+=+7 Subtract 4 from both sides.
i am sorry i cant understand what you wrote can you please explain to me again
Hello ^.^
5=lbs of popcorn c=lbs of caramel 80=cost per pound of popcorn (in cents) 240=cost per pound of caramel (in cents) 140=cost of both together (in cents) cost(lbs popcorn)+cost(lbs caramel)=cost(lbs popcorn and caramel) 80(5)+240(c)=140(5+c) 400+240c=700+140c Subtract 400 from both sides 240c=300+140c Subtract 140c from both sides 100c=300 Divide both sides by 100 c=3 Answer: 3 lbs of caramel
thank you soo much :)
Wow I can't understand what he wrote either lol
sorry my bad its Let x= the amount of caramel required 5*(0.80)+x(2.40)=(5+x)*(1.40) then simplify and solve for x
much better ha . i found the equation and tried to copy and paste i guess it didnt work
xD yupss
how would you solve for x
@brucebaner @keeks4481 can you please help me
I already did it.... it will be 3 x=3 So, the answer is 3 lbs of caramel
he's right ^^
ok thank you
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