Question

How to solve:
tan(theta) = 2/(-2 sqroot3)

Answer 1

\[\tan(\theta)=\frac{ 2 }{ -2\sqrt{3} }\]

Answer 2

\[\theta = \tan ^{-1}(\frac{ 2 }{ -2\sqrt{3} })\]

Answer 3

@Nnesha

Answer 4

@jim_thompson5910

Answer 5

can you cancel out 2's ??

Answer 6

multiply it by 2/2?

Answer 7

ooh I see what you're saying, sorry.

Answer 8

err can I?

Answer 9

then it would be \[\frac{ 1 }{ -\sqrt{3} }\]

Answer 10

\[\huge\rm tan(\theta) =\color{red}{-\frac{ 2 }{ 2\sqrt{3}} }\]
first of all solve red part :-)

Answer 11

\(\color{blue}{\text{Originally Posted by}}\) @Babynini
then it would be \[\frac{ 1 }{ -\sqrt{3} }\]
\(\color{blue}{\text{End of Quote}}\)
yes but you ca't have radical at the denominator so multiply top and bottom by sqrt{3}

Answer 12

\[\frac{ \sqrt{3} }{ 3 }\]

Answer 13

with a negative in front :P

Answer 14

\[\theta= \tan^{-1} (-\frac{\sqrt{3}}{3} )\]
from there do you wanna use a calculator or draw triangle ?

Answer 15

Triangle! Because what I need is it in radical form

Answer 16

(for example 5pi/6)

Answer 17

to make a triangle we know that it's not going to be in 1st and 3rd quadrant bec tan is positive in 1st and 3rd q