Question

Can someone check my answer?

What is the solution of the equation 2^x+1 = 5? Round your answer to the nearest ten-thousandth.

0.7565
1.3219**
2.3219
2.3974

Answer 1

xlog2=log4
x=log4/log2
I dont have a calc so im just showing the work and you check

Answer 2

2^x=5-1=4=2*2
2^x=2^2
wen base same then power is same x=2

Answer 3

\[2^{x-1}=5\]

Answer 4

Oh
then yeah its (x-1)log2 = log 5
so x-1=log5/log2
x- (log5/log2) + 1

Answer 5

wait is it x+1 or x-1?
youve written two different questions

Answer 6

x+1 @ Maisa101

Answer 7

@Maisa101

Answer 8

yeah so x= (log5/log2) -1

Answer 9

just plug into calc and solve

Answer 10

okay thanks

Answer 11

U write Q is wrong 2^(x+1)=5 is right way to written.