6=78+x29+=
Please, if you have learned the rules of priority of operations (PEMDAS), you need to apply them. f(6)=1/2x+x-4 without parentheses is equivalent to \(f(x)=\frac{1}{2}x+x-4\) which is likely NOT what you mean. If you want \(f(x)=\frac{1}{2x}+x-4\) you need to write \(f(x)=1/(2x)+x-4\) To evaluate f(6), replace by a "6" wherever the symbol x appears, i.e. f(6)=1/(2*6)+6-4 I'll let you complete the problem.
Please show your work how you got 14! :)
Did you use a calculator?
did you replace f(6)=1/(2*6)+6-4=14 by \(f(6)=1\div(2*6)+6-4=14\) and put in all the parentheses as shown? BTW, is it the first or second form of f(x) that you're supposed to do?
Do you have answer choices? I am not sure it is the first or second form of f(x) that you need. The best is if you could post an image of the question itself.
The problem is I am not sure if you have correctly reproduced the question. I need the original question (screen print, or scan of a paper question) to know.
That's a lot clearer. Yes, your original post was correct, i.e. f(x)=(1/2)*x+x-4 1/2 means 1 divided by 2. Use the \(\div\) key on your calculator. the * means multiply, use the \(\times\) key on your calculator. To find f(6), replace all occurrences of x by 6, and calculate the right hand side using the calculator: f(x)=(1/2)*6+6-4 Remember to put in all the symbols
Yes, what did you get?
That is correct! Well done!
Sorry it took a while to confirm the original question, but you were correct initially! :)
Yes, that is correct but I hear it rather shaky. You are sure you understand what you said?
Recall that a standard parabola has the equation y=x^2 and a more general parabola with a translation of the vertex is y=(x-h)^2 +k where (h,k) is the new vertex. So substituting (x+3)=x-h, we get h=-3 and k=-1, so the vertex is at (-3,-1). ok?
note: h is the horizontal translation to the right (h is negative if to the left). k is the vertical translation upwards (k is negative if downwards).
No. 2 is correct. but the coordinates are (2,-4),(5,-8). Your answer was based on the correct coordinates.
Join our real-time social learning platform and learn together with your friends!