Find a cubic function with the given zeros. -6, 7, -4 @jim_thompson5910 @dan815 @amistre64 @e.mccormick @kainui @sleepyjess @robtobey @eclipsedstar @precal
p(x)=(x+6)(x-7)(x+4)
recall (x-r) is your factor if you know that x=-3 then your factor form is (x+3)
okay so what do i do next @precal
well that is your answer unless they want you to expand it
f(x) = x3 + 3x2 + 46x - 168 f(x) = x3 + 3x2 - 46x + 168 f(x) = x3 - 3x2 - 46x - 168 f(x) = x3 + 3x2 - 46x - 168 these are my options @precal
expand it out
you can do it
i honestly cant figure it out @precal
did you not learn to expand binomials?
no @precal
(x+1)(x+4)
It is multiplication. That is it. Know how to FOIL a pair of binomials?
FOIL First Outer Inner Last
all you do is distribute x to (X+4) then distribute 1 to (x+4) then combine like terms
so its x^2+5x+4 right? @precal
yes now pick two of the three I gave you before and do the same, I will check your solution
like solve (x+6)(x-7)? @precal
yes you can do it, I will check your solution
is this the answer? f(x) = x3 + 3x2 - 46x + 168 @precal
Let's do it one step at a time what did you get for (x+6)(x-7)
x^2-x-42 @precal
yes now expand (x+4)(x^2-x-42) remember distribute x to (x^2-x-42) and then distribute 4 to (x^2-x-42) collect like terms
x^3+3x^2-46x-168 @precal
you got it !!!! GOOD JOB
did you understand the process?
can you help me with another one? @precal
ok what do you have?
State the domain of the rational function. f(x) = 12/13-x @precal
Easy the domain is all real numbers except 13 because 13 creates a zero in the denominator. Recall N/0 for no zero on the bottom Recall O/K Ok to have a zero on the top
one more? @precal
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 7, -11, and 2 + 8i f(x) = x4 - 9x3 - 56x2 + 290x - 5236 f(x) = x4 - 9x3 + 56x2 - 290x + 5236 f(x) = x4 - 145x2 + 580x - 5236 f(x) = x4 - 25x2 + 580x - 5236 these are my options @precal
ok just doing my calculus homework
sorry gotta distracted
(x-7)(x+11)(x-(2+8i))(x+(2+8i))
you need to multiply out the (x-(2+8i))(x+(2+8i)) first recall i^2 is -1
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