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Geometry 15 Online
OpenStudy (countrygirl1431):

@Here_to_Help15

OpenStudy (here_to_help15):

Yes Ma'am

OpenStudy (countrygirl1431):

Point (6, 0) lies on the x-axis y-axis line y = x would this be the y-axis

OpenStudy (countrygirl1431):

no no no the x- axis

OpenStudy (here_to_help15):

since it has a x-coordinate, it will lie on ?

OpenStudy (countrygirl1431):

x

OpenStudy (here_to_help15):

Since the Y-cordinate is 0. Therefore point (6, 0) lies on the X - axis

OpenStudy (here_to_help15):

x,0 --->x axis 0,y ----> y axis a,a ---> x=y line.

OpenStudy (countrygirl1431):

yaaaaah i got it right lol

OpenStudy (here_to_help15):

lol :)

OpenStudy (countrygirl1431):

If the equation of a circle is (x + 5)2 + (y - 7)2 = 36, its center point is (5, 7) (-5, 7) (5, -7)

OpenStudy (here_to_help15):

B

OpenStudy (here_to_help15):

I think you are saying (x + 5)^2 + (y -7)^2 = 36 the standard or canonical form of a circle is: X^2 + Y^2 = R^2 where R is the radius of the circle. It's just the pythagorean theorem for all possible values of X and Y. (Note, that possible values of x and y are only those which satisfy the equation.) So for your problem, let X= x +5 and Y = y -7 then R^2 = 36, so the radius R=6 the 5 and 7 just shift the center of the circle to x= -5 and y =+7.

OpenStudy (countrygirl1431):

i have no clue really what im saying lol

OpenStudy (here_to_help15):

im? lol or you*

OpenStudy (here_to_help15):

your*

OpenStudy (here_to_help15):

Well i got to go in 5 min

OpenStudy (countrygirl1431):

??????

OpenStudy (here_to_help15):

forget it lol just know the answer is B ;)

OpenStudy (countrygirl1431):

then ill be back to my lonesome self:(

OpenStudy (here_to_help15):

Aww il be back tomorrow :)

OpenStudy (here_to_help15):

Ill

OpenStudy (countrygirl1431):

really yaaaah im so happy :)

OpenStudy (here_to_help15):

:)

OpenStudy (countrygirl1431):

talk to u tomorrow then night

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