Question

Can someone check my answers?

Find the domain and range of ƒ−1 given f(x) = 3sqrt(x+8+1)
Domain: (−9, ∞) and Range: (−1, ∞)
Domain: (-∞, ∞) and Range: (-∞, ∞)**
Domain: (−8, ∞) and Range: (1, ∞)
Domain: (−7, ∞) and Range: (0, ∞)

Answer 1

HI!!

Answer 2

Hey

Answer 3

do this: find the domain of \(f\)
that will be the range of \(f^{-1}\)
then find the range of \(f\)
that will be the domain if \(f^{-1}\)

Answer 4

if you do not know how to find those, i can show you

Answer 5

for Domain (x+8+1) greeter and equal to zero

Answer 6

i am going to guess that there is a typo in the question

Answer 7

got Domain: (-∞, ∞) and Range: (-∞, ∞). So am I wrong?

Answer 8

is it
\[f(x)=3\sqrt{x+8}+1\] or maybe
\[f(x)=\sqrt[3]{x+8}+1\] i doubt it is what you wrote

Answer 9

\[\sqrt[3]{x+8+1}\]

Answer 10

The 2nd one. @misty1212

Answer 11

cubed root right?

Answer 12

you can take the cubed root of any number
so yeah \((-\infty,\infty)\)

Answer 13

So i'm right?

Answer 14

yes if it is cubed root

Answer 15

no one writes \(8+1\) though so i am confused
on planet earth it is called 9

Answer 16

that's how the question is

Answer 17

ok i believe you

Answer 18

lol okay

Answer 19

I don't see why u shouldn't