Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Convergence of this series?

OpenStudy (misty1212):

i used to love pacman

OpenStudy (anonymous):

\[\sum_{n=1}^{infinity} (-1)^n * n / \ln(n)\]

OpenStudy (anonymous):

xD Hahaha!

OpenStudy (misty1212):

those terms to not even go to zero if i am reading it right

OpenStudy (anonymous):

n=2*

OpenStudy (anonymous):

It is ((-1)^n * n) in the numerator.

OpenStudy (misty1212):

they do alternate, and if they alternate all you need is that they go to zero q

OpenStudy (misty1212):

but \[\lim_{n\to \infty}\frac{n}{\ln(n)}=\infty\]

OpenStudy (anonymous):

Oh.

OpenStudy (anonymous):

So it diverges, how would we show that b_n approaches infinty?

OpenStudy (misty1212):

show ?

OpenStudy (anonymous):

I mean it is obvious but do we have to show it? or can we just state it?

OpenStudy (misty1212):

it is obvious \(n\) grows way way (way) faster than \(\ln(n)\)

OpenStudy (anonymous):

Alrighty! Thanks :)

OpenStudy (misty1212):

for example \[\frac{1,000,000,000}{\ln(1,000,000,000}=\frac{1,000,000,000}{21}\]

OpenStudy (misty1212):

course if your teacher is a real pain, you could use l'hopital but it seems unnecessary to me

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!