Question

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
f(x)=x-7/x+3 and g(x)= -3x-7/x-1

Answer 1

f(g(x))= -3(x-7/x-3) / (x-7/x+3)-1
is this correct?

Answer 2

in f(g(x) put gx in place of x in f(x)

Answer 3

I already did that part so now do I have to plug in fx for gx?

Answer 4

yes.u need to find f(g(x) as well as g(f(x)

Answer 5

\[-3\frac { \frac{ x-7 }{ x-3} }{ \frac{ x-7 }{ x+3 }-1}\]

Answer 6

is this correct? but with -3 in the numerator

Answer 7

nope u need to write fx in gx only at place of x

Answer 8

I already did that part

Answer 9

3 is not at the bottom \[\huge\rm f(x) = \frac{ \color{red}{x}-7 }{ \color{red}{x}+3 }\]
replace x by \[\large\rm \color{red}{ \frac{ -3x-7 }{ \color{Red}{x-1} }}\]

Answer 10

which one is it
g(f(x)) or f(g(x) ?

Answer 11

nvm i got it's g(f(x))

Answer 12

you*

Answer 13

http://prntscr.com/778ajm

Answer 14

\[\huge\rm \frac { -3(\frac{ x-7 }{ x-3})-7 }{ \frac{ x-7 }{ x+3 }-1}\]
that's how it suppose to be

Answer 15

oh ok thanks so much

Answer 16

uhh now you have to solve this
(who made that q ) :(

Answer 17

yeah how should I start solving it?

Answer 18

should I distrubute the -3?

Answer 19

gimme a sec let me find shortcut ;D

Answer 20

ok thanks :)

Answer 21

yeah you have to distribute by -3 -.^

Answer 22

\[\frac{ \frac{ -2(5x-21) }{ x-3 } }{ \frac{ x-7 }{ x+3 }-1}\]

Answer 23

idk if I did it right lol

Answer 24

-2 ? where is it come from ?

Answer 25

ugh i typed it wrong

Answer 26

\[-\frac{ 2(5x - 21 }{ x-3 }\]

Answer 27

\[\huge\rm \frac { -3(\frac{ x-7 }{ x-3})-7 }{ \frac{ x-7 }{ x\color{Red}{-}3 }-1}\]
it's negative 3

Answer 28

multiply (x-7) by -3