Question

A turntable with a moment of inertia of 0.2 kgm^2 and a radius of 0.3 meters starts from rest. After 6 seconds, it's angular speed is 30 degrees radians/second.
A. What is the angular acceleration?
B. What angle does it turn through during the six second interval?
C. What is the torque on the turntable?

Answer 1

hint:
anglular acceleration \alpha is:
\[\alpha = \frac{\omega }{{\Delta t}}\]
where \omega is the gained angular speed, and \Delata t is time needed to gain that angular speed

Answer 2

Part B:
the requested angle \theta, is given by the subsequent formula:
\[\theta = \frac{{\omega {{\left( {\Delta t} \right)}^2}}}{2}\]

Answer 3

Part C:
whereas the requested torque M, is:
\[M = I\omega \]
where I is the moment of inertia