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Mathematics 21 Online
OpenStudy (anonymous):

fan and medal Alicia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space, as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 7? 4 over 36 5 over 36 6 over 36 8 over 36

OpenStudy (anonymous):

@starlord6200

OpenStudy (johnweldon1993):

Alright so out of ALL those combinations (how many are there) How many add to make 7? And then your probability would be \[\large P = \frac{\text{rolling a 7 total}}{\text{total possible outcomes}}\]

OpenStudy (anonymous):

im pretty sure there are 6 ways to get it and there is 36 combos so it has to be c

OpenStudy (johnweldon1993):

^Correct :) (1,6) (2,5) (3,4) (4,3) (5,2) (6,1) so \[\large P = \frac{6}{36}\]

OpenStudy (anonymous):

thanks both of u ^-^

OpenStudy (anonymous):

np ^-^

OpenStudy (anonymous):

to both of u lol

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