SEQUENCES QUESTIONS algebra 2 study guide help 1. what is the 17th term of the sequence that begins -3, 9, -27, 81...? 2. the fifth term of a geometric sequence is 120, and the seventh term is 30. What are the possible values of the sixth term of the sequence?
1. this is a geometric sequence a1, a1r , a1r^2, a1r^3 .... where a1 is the first term and r = common ratio the common ratio can be found by dividing the second term by the first so for this sequence r = 9 / -3 = -3
the formula for the nth term is a1(r)^(n-1) so for the 17th term of this sequence a1 = -3, n = 17 and r = -3
im a little confused as to what you mean there @welshfella
are you talking about my last post?
yes, if i plug it all in i should have -3(-3)^(17-1) right?
yes
im not sure if that computed correct because i got -129140163
you'll need to use your calculator of course!
yes Thats right
i did, i put in what i typed and got that long answer
alrighty, thanks! can you help me work out the next one?
yes thats correct these GP terms with a common ratio greater than 1 quickly get massive
seventh term = a1*r^6 fifth term = a1*r^4 dividing a1*r^6 / a1*r^4 = r^2 = 30/120 so r^2 = 1/4 and r = ?
what are the 2 square roots of 1/4?
im sorry, this one is confusing me a bit give me a sec
i don't know
sqrt 1/4 is 1/2 or -1/2 so the common ratio r = 1/2 or -1/2 to get the next term in the series you multiply by this value of r so as the 5th term is 120 the 6th term will be either 120 * 1/2 or 120 * -1/2
oh okay, that makes a little more since. so 120*1/2 and 120*-1/2 are my possible values for the sixth term, correct?
yes
perhaps i confused you a little with the formulas
the sequence would be either 120 , 60 ,30 or 120,-60,30
i must go right now
okay! thanks!
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