Question

PLEASE HELP
Write a sine function with a maximum of 0.5, a minimum of -0.5, and a period of 2(pi)/5.
WILL FAN AND MEDAL~ OuO

Answer 1

@dan815

Answer 2

Hey again :D

So we know the basic equation for a sine function is

\[\large Asin(Bx - C) + D\]

A is the amplitude (how high up and down the wave reaches)

B is the period (how often the wave repeats)

C is the phase shift

And D is the vertical displacement

Answer 3

So A...the amplitude will be the 0.5 that you want the sine wave to reach...

If the amplitude is the 0.5....the sine wave will oscillate between 0.5 and -0.5

Answer 4

And the B is our period...now the period of a sine wave is NORMALLY \(\large 2\pi \)

However the period can be calculated by using

\[\large Period = \frac{2\pi}{|B|}\]

Now here, since you're given the period to be \(\Large \frac{2\pi}{5}\)

So

\[\large Period = \frac{2\pi}{B} = \frac{2\pi}{5}\]

So we can see our B = 5

Answer 5

Now C and D we need not worry about...in this case they are both 0...

So altogether, our sine wave is

\[\large 0.5sin(5x)\]

Answer 6

sorry for the late responce!

Answer 7

thanks for explaining the formula, i can actually follow that!