Question

Need hypothesis testing help!!!

A real estate agent is working for a developer who claims that the average commute time to downtown is 20 minutes with a standard deviation of 7 minutes. Stephon is an independent real estate agent and wants to check the times for his client. He took a random sample of 15 commute times and found an average of 26 minutes. He did hypothesis testing using a significance level of 5%. Which conclusion could he make?
The z-statistic is 0.22, so the null hypothesis should not be rejected.
The z-statistic is 1.69, so the null hypothesis should not be rejected.
The z-statistic is 3.32, so the null hypothesis should be rejected.
The z-statistic is 3.67, so the null hypothesis should be rejected.

Answer 1

@kropot72

Answer 2

@jrain35 Do you know how to calculate the z-statistic?

Answer 3

no thats my problem with these questions :/

Answer 4

What learning resources have been made available to you?

Answer 5

none that i know of

Answer 6

What course are you taking?

Answer 7

Algebra 2

Answer 8

The formula for finding the z-statistic is as follows:
\[\large Z=\frac{\bar {X}-\mu}{\frac{\sigma}{\sqrt{n}}}\]

Answer 9

Plugging in the given values, we get:
\[\large Z=\frac{26-20}{\frac{7}{\sqrt{15}}}=you\ can\ calculate\]

Answer 10

so x is sample size?

Answer 11

or the mean?

Answer 12

I think its the mean

Answer 13

X-bar is the sample mean. Mu is the proposed value for the mean in the null hypothesis. Sigma is the standard deviation. n is the sample size.

Answer 14

alright thanks a ton

Answer 15

You're welcome :)