Question

Projectile is fired...say what? Help!

Answer 1

@acxbox22 :)

Answer 2

@rvc

Answer 3

@Michele_Laino :)

Answer 4

here we have to solve the first equation for t, so we can write:
\[t = \frac{x}{{{v_0}\cos \alpha }}\]
now we have to substitute that value fort, into the second equation, and we get:
\[y = {v_0}\sin \alpha \left( {\frac{x}{{{v_0}\cos \alpha }}} \right) - 16{\left( {\frac{x}{{{v_0}\cos \alpha }}} \right)^2}\]
After a simplification, we can write this:
\[y = x\tan \alpha - \frac{{16}}{{v_0^2{{\left( {\cos \alpha } \right)}^2}}}{x^2}\]
Please note that, the last equation is a parabola, in the plane x-y, which passes at the point(0,0), namely the origin of the coordinate system, and its concavity is downward!

Answer 5

Fabulous, thank you so much!!