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OpenStudy (anonymous):
What is the [Ca^+2] if you have a 3.0 M solution of [CaCl2(aq)]?
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OpenStudy (anonymous):
\[\color{green}{CaCl_2 \rightarrow Ca^{+2} + 2Cl^-}\] So, the concentration of the calcium ion would be the same as the original concentration of the calcium chloride, since it dissociates in a 1:1 ratio.
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