Question

Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random.



What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent.

Answer 1

@563blackghost

Answer 2

Follow these steps:
A) Number of red marbles = ?
B) Total number of marbles before first drawing = ?
C) Divide number in A) by number in B)
D) Number of yellow marbles = ?
E) Total number of marbles left after first drawing = ?
F) Divide number in D) by number in E)
G) Multiply number in C) by number in F)
H) Your solution is the product in G)

~ @mathstudent55

Answer 3

im confused O.o

Answer 4

Im typng out what it means...

Answer 5

A) The number of red marbles is 14
B) Total number of marbles....12+14=26
C) Divide the number in A (14) by the number of B (26)
D) The number of yellow marbles is 12
E) Since we drew 1 marble so 26-1=25
F) We divide the total of D (12) by the number in E (25)
G) Multiply the number in C (so the simplified form of 14/26) by F (the simplified form of 12/25)
H) Your solution is the product in G

Answer 6

48%?

Answer 7

What are your answer choices?

Answer 8

i have to type in a box and tell the percent

Answer 9

its not multiple choice

Answer 10

@563blackghost

Answer 11

one sec...

Answer 12

hmmm this one is tricky for me cause i got 56%

Answer 13

oh ok

Answer 14

im probably wrong...i was a lil bad at probability in the past...