Find the vertices and foci of the hyperbola with equation (4+x)^2/9-(y-5)^2/16=1

Question

Find the vertices and foci of the hyperbola with equation  (4+x)^2/9-(y-5)^2/16=1

kitten_is_back · Answer

have you start ed to try solving the problem love?

anonymous · Answer

No I have no idea how @Kitten_is_back

kitten_is_back · Answer

okay welplets start trying to solve the problem then

anonymous · Answer

Hey @Kitten_is_back I call people love. Why does everyone keep stealing my line

kitten_is_back · Answer

what do you think you have to do love?

kitten_is_back · Answer

its not a line love i just call people that because its a habit

anonymous · Answer

I have literally no idea @Kitten_is_back

anonymous · Answer

The general form of the hyperbola is (x-h)^2/a^2 -(y-k)^2/b^2 =1 
where the transverse axis is parallel to the x-axis. 
(h,k) is the center.

anonymous · Answer

Well are you from England?

kitten_is_back · Answer

:P ithink so i am not very sure :P

anonymous · Answer

I mean directly

anonymous · Answer

can you elaborate more @jackmullen55

kitten_is_back · Answer

mhm

anonymous · Answer

Vertices: (0, 5), (-8, 5); Foci: (-8, 5), (0, 5) 
 Vertices: (-1, 5), (-7, 5); Foci: (-9, 5), (1, 5) 
 Vertices: (5, 0), (5, -8); Foci: (5, -8), (5, 0) 
 Vertices: (5, -1), (5, -7); Foci: (5, -9), (5, 1) 
These are the options

anonymous · Answer

@mertsj